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Vector Potential

For T.E. radiation the components of the vector potential relative to the orthonormal basis are

$\displaystyle (\hat A_\xi,\hat A_\tau,\hat A_r,\hat A_\theta )$ $\textstyle =$ $\displaystyle \left(
0,0,\frac{-1}{r}
\frac{\partial\psi_F}{\partial \theta},\frac{\partial\psi_F}{\partial r}
\right)$  
  $\textstyle =$ $\displaystyle \left(
0,0,~~~~0~~~~,\frac{\pm4\pi a^2r}{(2\xi\xi')^2}
\left( \frac{u}{(u^2+1)^{3/2}} \dot q \mp \frac{1}{u^2+1} \ddot q
\right) \right)$ (79)

where an over-dot refers to the partial derivative

\begin{displaymath}
\dot q=\frac{\partial q (\tau\pm \sinh^{-1} u)}{\partial \tau} ~.
\end{displaymath}



Ulrich Gerlach 2001-10-09