randRange(5,9)*100 randRange(1,9)*10 randRange(1,9)*1 A+B+C (2) truncate_to_max(fruit_1_integer*pow(10,-fruit_1_decimal), 2) randRange(3,9)*100 randRange(1,9)*10 randRange(1,9)*1 D+E+F (2) truncate_to_max(fruit_2_integer*pow(10,-fruit_2_decimal), 2) truncate_to_max((fruit_1+fruit_2),2) []

{On a sunny morning|On a beautiful afternoon}, person(1) rode his(1) bicycle to a farm that sold bags of plural(fruit(1)) for \$fruit_1 each and bags of plural(fruit(2)) for \$fruit_2 each.

person(1) decided to buy a bag of plural(fruit(1)) and a bag of plural(fruit(2)) {before heading home|because those were his(1) favorite kinds of fruit|}.

How much did person(1) need to pay for his(1) produce?

fruit_1+fruit_2

To find the total amount person(1) needs to pay, we need to add the price of the plural(fruit(1)) and the price of the plural(fruit(2)).

Price of plural(fruit(1)) + price of plural(fruit(2)) = total price.

graph.adder = new DecimalAdder( fruit_1_integer, fruit_1_decimal, fruit_2_integer, fruit_2_decimal ); graph.adder.show(); graph.adder.showDecimals();
graph.adder.showHint();

person(1) needs to pay \$solution.

randRange(1, 3)*100 randRange(2000,9999) (2) truncate_to_max(time_1_integer*pow(10,-time_1_decimal), 2) randRange(2000,9999) (2) truncate_to_max(time_2_integer*pow(10,-time_2_decimal), 2) randRange(100,999) (2) truncate_to_max(time_3_integer*pow(10,-time_3_decimal), 2) [] truncate_to_max((time_1-time_2),2)

{On Monday|Last week}, person(1) and person(2) decided to see how fast they could sprint meters meters. They asked their friend person(3) to time them with a stopwatch.

{After time_3 minutes, person(3) agreed to time the runners.|} person(1) sprinted first and ran meters meters in time_1 seconds. When it was person(2)'s turn, he(2) sped off and completed the run in time_2 seconds.

How much faster was person(2) than person(1) in seconds?

time_1-time_2 seconds

To find how much faster person(2) was than person(1), we need to find the difference between their times in seconds.

person(1)'s time - person(2)'s time = difference in times.

graph.subtractor = new DecimalSubtractor( time_1_integer, time_1_decimal, time_2_integer, time_2_decimal ); graph.subtractor.show(); graph.subtractor.showDecimals();
graph.subtractor.showHint();

person(2) was solution seconds faster than person(1).

randRange(2,6)*100 randRange(1,9)*10 randRange(1,9)*1 G+H+I (2) truncate_to_max(weight_1_integer*pow(10,-weight_1_decimal), 2) randRange(3,5)*100 randRange(1,9)*10 randRange(1,9)*1 J+K+L (2) truncate_to_max(weight_2_integer*pow(10,-weight_2_decimal), 2) randRange(16.5,22.5) randRange(16.5,22.5) truncate_to_max((weight_1+weight_2),2) []

{Last Monday|On Saturday}, person(1)'s parents gave birth to twins and named them person(2) and person(3). When they were first born, person(2) weighed weight_1 pounds{ and was height_1 inches tall|}, and person(3) weighed weight_2 pounds {and was height_2 inches tall|}.

How much did the babies weigh in total?

weight_1+weight_2 pounds

To find the weights of the 2 babies, we need to add their weights together.

person(2)'s weight + person(3)'s weight = total weight.

graph.adder = new DecimalAdder( weight_1_integer, weight_1_decimal, weight_2_integer, weight_2_decimal ); graph.adder.show(); graph.adder.showDecimals();
graph.adder.showHint();
graph.adder.showHint();

Together, the babies weigh solution pounds.

randRange(1,9) randRange(1,9) randRange(2,9) M*100+N*10+O (2) truncate_to_max(amount_paid_integer*pow(10,-amount_paid_decimal), 2) randRange(1,M)*100 randRange(1,N)*10 randRange(1,O)*1 P+Q+R (2) truncate_to_max(price_1_integer*pow(10,-price_1_decimal), 2) randRange(3, 30) truncate_to_max((amount_paid-price_1),2) []

{On Tuesday,|Last Thursday,|} person(1) walked to an(store(1)) store {timeofday(1)|} and{, after browsing for time_1 minutes,|} decided to buy a storeItem(1,1) for \$price_1. person(1) handed the salesperson \$amount_paid for his(1) purchase.

How much change did person(1) receive?

amount_paid-price_1

To find out how much change person(1) received, we can subtract the price of the storeItem(1,1) from the amount of money he(1) paid.

The amount person(1) paid - the price of the storeItem(1,1) = the amount of change person(1) received.

graph.subtractor = new DecimalSubtractor( amount_paid_integer, amount_paid_decimal, price_1_integer, price_1_decimal ); graph.subtractor.show(); graph.subtractor.showDecimals();
graph.subtractor.showHint();

person(1) received \$solution in change.

randRange(101,999) (2) truncate_to_max(rain_1_integer*pow(10,-rain_1_decimal), 2) randRange(rain_1_integer+1,999) (2) truncate_to_max(rain_2_integer*pow(10,-rain_2_decimal), 2) randRange(2.1,15.89) [] truncate_to_max((rain_2-rain_1),2)

During a recent rainstorm, rain_1 inches of rain fell in person(1)'s hometown, and rain_2 inches of rain fell in person(2)'s hometown. {During the same storm, snow_1 inches of snow fell in person(3)'s hometown.|}

How much more rain fell in person(2)'s town than in person(1)'s town?

rain_2-rain_1 inches

To find the difference in rainfall, we can subtract the amount of rain in person(1)'s town from the amount of rain in person(2)'s town.

Rain in person(2)'s town - rain in person(1)'s town = the difference in rain between the two towns.

graph.subtractor = new DecimalSubtractor( rain_2_integer, rain_2_decimal, rain_1_integer, rain_1_decimal ); graph.subtractor.show(); graph.subtractor.showDecimals();
graph.subtractor.showHint();

person(2)'s town received solution inches more rain than person(1)'s town.

randRange(100,2000) (2) truncate_to_max(distance_1_integer*pow(10,-distance_1_decimal), 2) randRange(100,distance_1_integer-1) (2) truncate_to_max(distance_2_integer*pow(10,-distance_2_decimal), 2) truncate_to_max((distance_1+distance_2),2) randRange(20.2,52.17) []

{To get to school each morning|To get to work each morning|To visit his(1) grandmother}, person(1) takes an(vehicle(1)) distance_1 plural(distance(1)) and an(vehicle(2)) distance_2 plural(distance(1)). {In total, the journey takes time_1 minutes.|}

How many plural(distance(1)) is person(1)'s journey in total?

distance_1+distance_2 plural(distance(1))

To find the total distance person(1) travels, we need to add the two distances together.

Distance on vehicle(1) + distance on vehicle(2) = total distance.

graph.adder = new DecimalAdder( distance_1_integer, distance_1_decimal, distance_2_integer, distance_2_decimal ); graph.adder.show(); graph.adder.showDecimals();
graph.adder.showHint();
graph.adder.showHint();

person(1) travels solution plural(distance(1)) in total.