randRange(6, 20) * randRangeNonZero(-1, 1) randRange(2, 6) randRangeNonZero(2, 8 - DIFFERENCE) + DIFFERENCE DIFFERENCE * randRange(2, 15)
A - DIFFERENCE A * SOLUTION + B - C * SOLUTION max(30, min(150, A * SOLUTION + B)) shuffle(randFromArray([[2, 4], [3, 5]]))

The two horizontal lines are parallel, and there is a third line that intersects them as shown below.

Solve for x:

SOLUTION

var eq1 = A + "x + " + B + "^\\circ"; var eq2 = C + "x + " + D + "^\\circ"; init({ range: [[-1, 11], [-1, 4]] }); graph.pl = new ParallelLines(0, 0, 10, 0, 3); graph.pl.draw(); graph.pl.drawMarkers(ANGLE); graph.pl.drawTransverse(ANGLE); graph.pl.drawAngle(KNOWN_INDEX, eq1); graph.pl.drawAngle(UNKNOWN_INDEX, eq2, "#FFA500");

Alternate exterior angles are equal to one another. Watch this video to understand why.

The \color{BLUE}{\text{blue angle}} and the \color{ORANGE}{\text{orange angle}} are alternate exterior angles. Therefore, we can set them equal to one another.

\color{BLUE}{Ax + B} = \color{ORANGE}{Cx + D}

Subtract \color{PINK}{Cx} from both sides.

(Ax + B) \color{PINK}{- Cx} = (Cx + D) \color{PINK}{- Cx}

A - Cx + B = D

B > 0 ? "Subtract" : "Add" \color{PINK}{abs(B)} B > 0 ? "from" : "to" both sides.

(A - Cx + B) \color{PINK}{+ -B} = D \color{PINK}{+ -B}

A - Cx = D - B

Divide both sides by \color{PINK}{A - C}.

\dfrac{A - Cx}{\color{PINK}{A - C}} = \dfrac{D - B}{\color{PINK}{A - C}}

Simplify.

x = SOLUTION

Subtract \color{PINK}{Ax} from both sides.

(Ax + B) \color{PINK}{- Ax} = (Cx + D) \color{PINK}{- Ax}

B = C - Ax + D

D > 0 ? "Subtract" : "Add" \color{PINK}{abs(D)} D > 0 ? "from" : "to" both sides.

B \color{PINK}{+ -D} = (C - Ax + D) \color{PINK}{+ -D}

B - D = C - Ax

Divide both sides by \color{PINK}{C - A}.

\dfrac{B - D}{\color{PINK}{C - A}} = \dfrac{C - Ax}{\color{PINK}{C - A}}

Simplify.

SOLUTION = x