Plotting points on a coordinate plane and tell quadrant. Common Core State Standard: 6.NS.6c Related Videos: Quadrants of Coordinate Plane, The Coordinate Plane Prerequisite: Number line, (coming soon) Plotting points 0.5 Required/helpful For: Graphing linear equations, (coming soon) Graphing using x and y intercepts
randRangeNonZero( -10, 10 ) randRangeNonZero( -10, 10 ) X > 0 ? ( Y > 0 ? "QI" : "QIV" ) : ( Y > 0 ? "QII" : "QIII" )

Plot (X, Y) and select the quadrant in which the point lies.


graphInit({ range: 11, scale: 20, axisArrows: "<->", tickStep: 1, labelStep: 1, gridOpacity: 0.05, axisOpacity: 0.2, tickOpacity: 0.4, labelOpacity: 0.5 }); label( [ 0, 11 ], "y", "above" ); label( [ 11, 0 ], "x", "right" ); addMouseLayer(); graph.movablePoint = addMovablePoint({ coord: [ 0, 0 ], snapY: 1, snapX: 1 }); graph.movablePoint.onMove = function( x, y ) { return [ max( -10, min( x, 10 ) ), max( -10, min( y, 10 ) ) ]; };
Graph the point and select the quadrant that contains the point.
Your graph is also part of your answer.
[ graph.movablePoint.coord, $( "#solutionarea" ).find( "input:checked" ).val() ]
if ( guess[ 0 ][ 0 ] === 0 && guess[ 0 ][ 1 ] === 0 && guess[ 1 ] == null ) { return ""; } return guess[ 0 ][ 0 ] === X && guess[ 0 ][ 1 ] === Y && guess[ 1 ] === QUADRANT;
graph.movablePoint.setCoord( guess[0] );
$( "#solutionarea" ).find( "input" ).prop( 'checked', false ); if ( guess[ 1 ] != null ) { $( "#solutionarea" ).find( "input[value=" + guess[ 1 ] + "]" ).prop( 'checked', true ); }

Coordinates are listed as (\blue{x},\green{y}).

So, for ( \blue{X}, \green{Y} ) our x-coordinate is \blue{X} and our y-coordinate is \green{Y}.

The x-coordinate tells how far we move to the right from the origin and the y-coordinate tells us how far we move up from the origin.

Since our x-coordinate is positivenegative, we move \blue{abs( X )} to the rightleft.

style({ stroke: BLUE, strokeWidth: 3, arrows: "->" }, function() { line( [ 0, 0 ], [ X, 0 ]); }); graph.movablePoint.toFront();

Since our y-coordinate is positive negative, we move \green{abs( Y )} up down.

style({ stroke: GREEN, strokeWidth: 3, arrows: "->" }, function() { line( [ X, 0 ], [ X, Y ] ); }); graph.movablePoint.toFront();

Move the point to ( \blue{X}, \green{Y} ) at the marked point above.

style({ stroke: PINK, strokeWidth: 3 }, function() { line( [ X - 0.3, Y - 0.3 ], [ X + 0.3, Y + 0.3 ] ); line( [ X + 0.3, Y - 0.3 ], [ X - 0.3, Y + 0.3 ] ); }); graph.movablePoint.toFront();

Now that we have our point plotted, we can figure out the quadrant.

By convention, quadrants are named with a capital \text{Q} and a roman numeral, starting in the upper right quadrant as \text{QI} and rotating counter-clockwise.

label( [ 5, 5] , " \\text{ QI }", "center", { color: "purple" } ); label( [ -5, 5] , " \\text{ QII }", "center", { color: "purple" } ); label( [ -5, -5] , " \\text{ QIII }", "center", { color: "purple" } ); label( [ 5, -5] , " \\text{ QIV }", "center", { color: "purple" } );

Since our point is in the upperlower rightleft portion of the graph, the quadrant is \purple{\text{QUADRANT}}.