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Next: Flow of Radiant T.M. Up: RADIATED POWER Previous: Electric Dipole and its

Flow of Radiant T.E. Field Energy

Any loop antenna radiates only for a finite amount of time. Consequently, one can calculate the flow of total emitted energy, which is given by the spatial integral, Eq.(57). The fact that $\theta$ is a cyclic coordinate for axially symmetric sources and radiation implies that $\hat E_r=\hat B_\theta
=0$ for the T.E. field. Consequently, the spatial integral, a conserved quantity independent of time $\xi$, reduces with the help of the table of derivatives in Section IV to

$\displaystyle \int_{-\infty}^\infty \int_0^\infty \int _0^{2\pi} T^\xi_{~\tau}\,\xi d\tau
\, rdr \,d\theta$ $\textstyle =$ $\displaystyle \int_{-\infty}^\infty \int_0^\infty \int _0^{2\pi}
\frac{1}{4\pi}\hat B_r \times\hat E_\theta \xi \,\xi d\tau \, rdr \,d\theta$ (65)
  $\textstyle =$ $\displaystyle \frac{1}{4\pi}\int_0^\infty \int_0^\infty \int _0^{2\pi}
\frac{1}...
...partial r} \frac{\partial \psi_F}{\partial \xi}\xi
\,\xi d\tau \, rdr \,d\theta$  
  $\textstyle =$ $\displaystyle (\pm)\frac{(\pi a^2)^2}{\xi'^4_{I,II}}\int_{-\infty}^\infty
\frac...
...u^3}\right) ^2
+\left( \frac{d^2q_{I,II}(\tau)}{d\tau^2}\right)^2
\right\}d\tau$ (66)

The computation leading to the last line has been consigned to the Appendix. This computed quantity is the total energy flow (energy $\times$ velocity), or equivalently, the total momentum into the $\tau$-direction, radiated by a magnetic dipole accelerated uniformly in Rindler sector $I$ (upper sign) or in Rindler sector $II$ (lower sign).

The full scalar radiation field

$\displaystyle \psi_F(\xi,\tau,r,\theta)=2\pi a^2
\frac{\pm 1}{\sqrt{(\xi^2-\xi^{'2}_I -r^2)^2+(2\xi \xi'_I)^2}}
\frac{dq_{I,II}(\tau')}{d\tau}~,$     (67)

with

\begin{displaymath}
\tau'=\tau \pm \sinh^{-1}\frac{\xi^2-\xi^{'2}_{I,II} -r^2}{2\xi \xi'_{I,II}}~,
\end{displaymath}

is a linear functional correspondence. It maps the temporal history $q_{I,II}(\tau')$ at $\xi'=\xi'_{I,II}$ in Rindler sector $I$ (resp. $II$) with 100% fidelity onto a readily measurable e.m. field along the $\tau$-axis (or a line parallel to it) on the spatial hypersurface $\xi=const.$ in Rindler sector $F$. This correspondence has 100% fidelity because, aside from a $\tau$-independent factor, the source history $q_{I,II}(\tau')$ and the scalar field $\psi_F(\tau)$ differ only by a constant $\tau$-independent shift on their respective domains $-\infty<\tau'<\infty$ and $-\infty<\tau<\infty$. This implies that
\begin{displaymath}
\frac{\partial}{\partial\tau'}=\frac{\partial}{\partial\tau}
\end{displaymath} (68)

when applied to the source function $q_{I,II}$. The expression for the radiated momentum becomes more transparent physically if one uses the proper time derivative

\begin{displaymath}
\frac{d}{dt'} \equiv
\frac{1}{\xi'}\frac{\partial}{\partial\tau'}
=\frac{1}{\xi'}\frac{\partial}{\partial\tau}
\end{displaymath}

at the source. Introduce the (proper) magnetic moment of the current loop having radius $a$:

\begin{displaymath}
\textbf{m}=\pi a^2 \frac{1}{\xi'}\frac{\partial q}{\partial \tau'} ~.
\end{displaymath}

One finds from Eq.(66) that the proper radiated longitudinal momentum (i.e. physical, a.k.a. orthonormal, component of energy flow pointing into the $\tau$-direction) measured per proper spatial $\tau$-interval $\xi\, d\tau$ in $F$ is
\begin{displaymath}
{\mathcal I}_{T.E.}=
(\pm)~\frac{\xi'^2}{\xi^2} \frac{2}{3}\...
...ac{1}{\xi'^2}\left(\frac{d \textbf{m}}{dt'}\right)^2 \right]~.
\end{displaymath} (69)

This is the formula for the proper radiant energy flow due to a magnetic dipole moment subject to uniform linear acceleration $1/\xi'$. There are two factors of $1/\xi$. The the first converts the coordinate $\tau$-momentum component into its physical component. The second is due to the fact that Eq.(69) expresses this quantity per proper distance into the $\tau$ direction.

When the acceleration $1/\xi'$ is small then the second term becomes small compared to the first. In fact, one recovers the familiar Larmor formula [#!Landau1962!#] relative to a static inertial frame by letting $\xi=\xi'$ and letting $1/\xi'\rightarrow 0$, which corresponds to inertial motion. By contrast, Eq.(69) is the correct formula for an accelerated dipole moment. However, observation of radiation from such a source entails that the measurements be made relative to an expanding inertial reference frame.


next up previous
Next: Flow of Radiant T.M. Up: RADIATED POWER Previous: Electric Dipole and its
Ulrich Gerlach 2001-10-09